Degree 10: T₄₁

Name(s): [1/2.S(5)^2]2=[A(5):2]2

Order: 14400 = 2⁶ · 3² · 5²

Parity: -1

|Aut(K)|=|C_S10(G)|= 1

Subfields: 2T1

Other representations: 12T279, 20T456, 20T459

Resolvents
  2: 2T1, 2T1, 2T1
  4: 4T2