Degree 10: T4

Name(s): 1/2[F(5)]2

Order: 20 = 22 · 5

Parity: -1

|Aut(K)|=|CS10(G)|= 2

Subfields: 2T1, 5T3

Other representations: 5T3, 20T5

Resolvents
  2: 2T1
  4: 4T1