Degree 12: T220

Name(s): M_10.2(12)=A_6.E_4(12)=[S_6[1/720]{M_10}S_6]2

Order: 1440 = 25 · 32 · 5

Parity: 1

|Aut(K)|=|CS12(G)|= 1

Subfields: 2T1

Other representations: 10T35, 20T201, 20T204, 20T208

Resolvents
  2: 2T1, 2T1, 2T1
  4: 4T2