Degree 14: T1

Name(s): C(14)=7[x]2

Order: 14 = 2 · 7

Parity: -1

|Aut(K)|=|CS14(G)|= 14

Subfields: 2T1, 7T1

Other representations: none

Resolvents
  2: 2T1
  7: 7T1