Degree 15: T1

Name(s): C(15)=5[x]3

Order: 15 = 3 · 5

Parity: 1

|Aut(K)|=|CS15(G)|= 15

Subfields: 3T1, 5T1

Other representations: none

Resolvents
  3: 3T1
  5: 5T1