Degree 15: T100

Name(s): [1/2.S(5)^3]S(3)

Order: 5184000 = 29 · 34 · 53

Parity: -1

|Aut(K)|=|CS15(G)|= 1

Subfields: 3T2

Other representations: 18T955

Resolvents
  2: 2T1
  6: 3T2
  24: 4T5