Degree 8: T12

Name(s): 2A_4(8)=[2]A(4)=SL(2,3)

Order: 24 = 23 · 3

Parity: 1

|Aut(K)|=|CS8(G)|= 2

Subfields: 4T4

Other representations: none

Resolvents
  3: 3T1
  12: 4T4